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7v^2-44v-35=0
a = 7; b = -44; c = -35;
Δ = b2-4ac
Δ = -442-4·7·(-35)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-54}{2*7}=\frac{-10}{14} =-5/7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+54}{2*7}=\frac{98}{14} =7 $
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